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y^2-37y+36=0
a = 1; b = -37; c = +36;
Δ = b2-4ac
Δ = -372-4·1·36
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-35}{2*1}=\frac{2}{2} =1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+35}{2*1}=\frac{72}{2} =36 $
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